ЖК Соловьиная роща | Галерея

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Как будет выглядеть ваш дом

3D-визуализации

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Примеры интерьеров

Фактическая визуализация

Вид отделки

Ход строительства жилого дома № 6 за январь 2017г.

Ход строительства жилого дома № 6 за февраль 2017 г.

Ход строительства жилого дома № 6 за март 2017г.

Ход строительства жилого дома № 6 за апрель 2017г.

Ход строительства жилого дома за май 2017г.

Ход строительства жилого дома за июнь 2017г.

Ход строительства жилого дома № 7 за январь 2017г.

Ход строительства жилого дома № 7 за февраль 2017г.

Ход строительства жилого дома № 7 за март 2017г.

Ход строительства жилого дома № 7 за апрель 2017г.

Ход строительства жилого дома № 7 за май 2017г.

Ход строительства жилого дома № 7 за июнь 2017г.

Общее выполнеия сценариев:
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составило
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Время выполнения запроса: SELECT * FROM node_sites WHERE id='3272'
параметры:
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составило
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Время выполнения CMSCore
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составило
9.5E-5
Время выполнения CallMe
0.002372
Время выполнения Form
0.001472
Время выполнения CallMe2
0.001106
Время выполнения Form
0.000613
Время выполнения Gallery
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Время выполнения запроса: SELECT n.*, m.sortorder FROM gallery n INNER JOIN main m ON m.id=n.id AND m.visible=1 INNER JOIN node_sites dd ON dd.id=n.parent_id AND n.parent_id = '3272' INNER JOIN main m2 ON m2.id=n.id AND m2.visible=1 ORDER BY m.sortorder asc LIMIT 0,200
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составило
0.002799
Время выполнения MenuNav
0.001902
Время выполнения запроса: SELECT DISTINCT t.* FROM ( (SELECT DISTINCT m1.id, IFNULL(m1.parent_id,0) as parent_id, n1.name as name, n1.URL as url, m1.SORTORDER FROM node_sites n1, main m1 WHERE m1.id = n1.id AND m1.visible = 1 AND n1.in_menu = 1) UNION ALL (SELECT DISTINCT m2.id, IFNULL(m2.parent_id,0) as parent_id, n2.name as name, n2.URL as url, m2.SORTORDER FROM genplan n2, main m2 WHERE m2.id = n2.id AND m2.visible = 1 AND n2.in_menu = 1) UNION ALL (SELECT DISTINCT m3.id, IFNULL(m3.parent_id,0) as parent_id, n3.name as name, n3.URL as url, m3.SORTORDER FROM faq n3, main m3 WHERE m3.id = n3.id AND m3.visible = 1 AND n3.in_menu = 1) UNION ALL (SELECT DISTINCT m4.id, IFNULL(m4.parent_id,0) as parent_id, n4.name as name, n4.URL as url, m4.SORTORDER FROM mnews n4, main m4 WHERE m4.id = n4.id AND m4.visible = 1 AND n4.in_menu = 1) UNION ALL (SELECT DISTINCT m5.id, IFNULL(m5.parent_id,0) as parent_id, n5.name as name, n5.URL as url, m5.SORTORDER FROM actions n5, main m5 WHERE m5.id = n5.id AND m5.visible = 1 AND n5.in_menu = 1)) as t order by t.SORTORDER составило
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Время выполнения запроса: SELECT * FROM config cfg LIMIT 0,1 составило
0.000168
Время выполнения SubMenu
0.000602
Время выполнения запроса: SELECT DISTINCT t.* FROM ( (SELECT DISTINCT m0.id, IFNULL(m0.parent_id,0) as parent_id, n0.name as name, n0.URL as url, m0.sortorder FROM node_sites n0, main m0 WHERE m0.id = n0.id AND m0.visible = 1 AND n0.parent_id = 1003) UNION ALL (SELECT DISTINCT m1.id, IFNULL(m1.parent_id,0) as parent_id, n1.name as name, n1.URL as url, m1.sortorder FROM mnews n1, main m1 WHERE m1.id = n1.id AND m1.visible = 1 AND n1.parent_id = 1003) UNION ALL (SELECT DISTINCT m2.id, IFNULL(m2.parent_id,0) as parent_id, n2.name as name, n2.URL as url, m2.sortorder FROM actions n2, main m2 WHERE m2.id = n2.id AND m2.visible = 1 AND n2.parent_id = 1003) UNION ALL (SELECT DISTINCT m3.id, IFNULL(m3.parent_id,0) as parent_id, n3.name as name, n3.URL as url, m3.sortorder FROM gallery n3, main m3 WHERE m3.id = n3.id AND m3.visible = 1 AND n3.parent_id = 1003)) as t order by t.sortorder составило
0.000468